📏 1 · The Basics — what a logarithm is
A logarithm is just a tidy way to write the question "what power do I raise this number to?". It is the inverse of an exponential.
If ax = N ⇔ loga N = x"What power of a gives N?" — that answer is the logarithm of N to base a. So log10 1000 = 3 means "10 multiplied by itself 3 times gives 1000".
1.1 Three parts of a log expression
- Base (a) — the number being multiplied. Must be positive and ≠ 1.
- Argument (N) — the result you reach. Must be positive.
- Log value (x) — how many times the base was multiplied. Can be any real number (positive, negative, zero, fractional).
1.2 The two bases NEET cares about
| Name | Symbol | Base | Where it appears |
|---|---|---|---|
| Common log | log N or log10 N | 10 | pH, pOH, pKa, Nernst, decibels |
| Natural log | ln N or loge N | e ≈ 2.718 | Arrhenius, radioactive decay, exponential growth |
📏 2 · Basic Identities
| Rule | Formula | Plain meaning |
|---|---|---|
| Log of 1 | loga 1 = 0 | Any base to the power 0 is 1. |
| Log of the base | loga a = 1 | Base raised to power 1 is itself. |
| Log of a base-power | loga(ax) = x | Read the exponent off directly — base "cancels". |
| Inverse identity | aloga N = N | Power and log are inverses — they undo each other. |
| One-to-one | If loga x = loga y, then x = y | Different inputs give different log values. |
| Equal bases & arguments | If loga x = logb x & x ≠ 1, then a = b | Equal logs at the same non-trivial argument force equal bases. |
📏 3 · The Three Operation Rules (most useful!)
| Rule | Formula | Plain meaning |
|---|---|---|
| Product | log(xy) = log x + log y | Multiply two numbers → ADD their logs. |
| Quotient | log(x/y) = log x − log y | Divide → SUBTRACT logs. |
| Reciprocal | log(1/x) = − log x | Reciprocal of x flips the sign of log x. |
| Negative power | log(x−n) = −n · log x | Negative exponent flips the sign and pulls the coefficient out. |
| General product chain | log(x₁ x₂ x₃ …) = Σ log xᵢ | Multiplying any number of factors → sum the logs. |
Multiplication is hard, addition is easy. Logs turn multiplications INTO additions and divisions into subtractions. That's why slide-rules used to be the world's calculators before computers existed.
📏 4 · Power & Root Rules
| Rule | Formula | Plain meaning |
|---|---|---|
| Power | log(xn) = n · log x | Pull the power out as a multiplier — the single most-used log rule in NEET kinetics. |
| Root | log(n√x) = (1/n) · log x | Same as power rule with fractional exponent 1/n. |
| Square root | log √x = (1/2) log x | Special case of the root rule. |
| Power in base | logan x = (1/n) · loga x | Raise the BASE to a power → divide the log by n. |
| Power on both sides | logan xm = (m/n) · loga x | Combine the two above. |
log(8³) = 3 · log 8 = 3 · 3 log 2 = 9 × 0.30 = 2.71
log9 27 = log3²(3³) = (3/2) · log3 3 = 3/2
4.1 Nested / Tower Powers — log(xyz) and log((xy)z)
These two look similar but they are different. The standard convention for exponentiation is right-associative, so xyz means x(yz), not (xy)z.
| Expression | What it means | Apply log → answer |
|---|---|---|
log(xyz) | log(x(yz)) (tower) | yz · log x |
log((xy)z) | log(xyz) (rule of indices) | yz · log x |
log(xy · xz) | log(xy+z) | (y + z) · log x |
log(xy/xz) | log(xy−z) | (y − z) · log x |
The power rule log(xn) = n · log x works no matter what shape n has. n can be a number (3), a variable (y), a product (yz), a sum (y + z), a power (yz), or even another logarithm. Whatever sits in the exponent comes out as the multiplier — full stop.
4.2 Step-by-step worked examples
log(232). The exponent is 3² = 9. So log(2⁹) = 9 · log 2 = 9 × 0.30 = 2.70.
Compare with log((2³)²) = log(2⁶) = 6 · log 2 = 6 × 0.30 = 1.80. Notice the two are completely different.
Simplify log(xyz).
Apply the power rule with n = yz: → yz · log x.
If you also want to crack yz, take a second log: log(yz · log x) = z · log y + log(log x). (You can keep peeling layers off.)
Simplify log(xxx).
The exponent is xx. → xx · log x. (Then if you take log of the result you can split xx further as x · log x + log(log x).)
Simplify log((x2)3).
Brackets force the rule of indices first: (x²)³ = x2·3 = x⁶.
→ log(x⁶) = 6 · log x.
Differentiate y = x(sin x).
Take log: log y = sin x · log x (the power sin x comes out front).
Differentiate both sides: (1/y) · dy/dx = cos x · log x + sin x · (1/x).
So dy/dx = x(sin x)·[cos x · log x + sin x/x].
log(xyz) = yz · log x. That's wrong. yz is what you get from (xy)z only. The pure tower without brackets gives yz·log x.4.3 What about logxy(xz)?
Use the "power in BOTH" rule (4.2 of section 4 main table):
logxy(xz) = (z/y) · logx x = z/ylog4 32 = log2² 2⁵ = 5/2 = 2.5.
📏 5 · Change of Base & Base Swapping
| Rule | Formula | Plain meaning |
|---|---|---|
| Change of base | logb x = loga x / loga b | Convert from any base to any other — divide by the log of the new base. |
| Swap base ↔ argument | loga b = 1 / logb a | Swap the base and the argument → take the reciprocal. |
| Product of swaps | loga b · logb a = 1 | Direct consequence of swap rule. |
| Three-base chain | loga b · logb c = loga c | "Chain rule" — the middle base cancels. |
| n-base chain | loga₁ a₂ · loga₂ a₃ · … · logaₙ₋₁ aₙ = loga₁ aₙ | Generalisation of three-base chain. |
log2 32 = log 32 / log 2 = (5 log 2) / log 2 = 5 (since 25 = 32)
📏 6 · Natural Log ↔ Common Log Conversion
| Rule | Formula | Plain meaning |
|---|---|---|
| ln to log | ln x = 2.303 · log10 x | The single most-used conversion in chemistry kinetics — multiply log by 2.303. |
| log to ln | log10 x = 0.4343 · ln x | = ln x / 2.303 = ln x · log e. |
| ln of ex | ln(ex) = x | Natural log and exponential cancel. |
| e to the ln | eln x = x | The other direction also cancels. |
| 10 to the log | 10log x = x | "Antilog of log of x is x." |
| ln 1 / ln e / ln 10 | ln 1 = 0, ln e = 1, ln 10 = 2.303 | Anchors. |
ln 10. Memorise it once — it appears in Arrhenius, Nernst, radioactive decay, ΔG° = −RT ln K conversion to −2.303 RT log K, and the integrated first-order rate law.📏 7 · Sign & Domain Rules
| Situation | Value of log10 x | Why |
|---|---|---|
| x > 1 | Positive | x is bigger than 10⁰ = 1. |
| x = 1 | 0 | Any base to power 0 = 1. |
| 0 < x < 1 | Negative | Need a negative power of 10 to shrink past 1. |
| x = 0 | Undefined (→ −∞) | No finite power makes a positive base equal 0. |
| x < 0 | Undefined (in real numbers) | No real exponent of a positive base gives a negative. |
| Base a ≤ 0 or a = 1 | Not allowed | Base must be positive and ≠ 1. |
Logs only know how to handle positive arguments. Zero is the cliff edge (log → −∞), negatives fall off the cliff entirely (no real value).
📏 8 · Inequality (Monotonicity) Rules
| If… | Then… |
|---|---|
Base a > 1 & x > y > 0 | loga x > loga y (log is increasing) |
Base 0 < a < 1 & x > y > 0 | loga x < loga y (log is decreasing — flips!) |
| For any base, x = y | log x = log y |
| x = y means base & argument identical | log = 1 |
For "normal" bases (10 or e), the log function is increasing: bigger input → bigger log. NEET / JEE always uses base > 1, so the second case rarely shows up.
📏 9 · Useful Derived Results
| Rule | Formula |
|---|---|
| Sum of log → log of product | log a + log b + log c = log(abc) |
| Coefficient of log → log of power | n · log a = log(an) |
| Log of a quotient power | log((a/b)n) = n · (log a − log b) |
| Log of a square root quotient | log √(a/b) = ½(log a − log b) |
| Log of factorial (large n) | log 1 + log 2 + log 3 + … + log n = log(n!) |
| Log of m · √n | log(m·√n) = log m + ½ log n |
| Log of ekx | ln(ekx) = kx |
| Log of a · 10n | log(a × 10n) = log a + n (scientific notation) |
log(3.16 × 10⁻⁵) = log 3.16 − 5 ≈ 0.5 − 5 = −4.5 → pH = 4.5.∑ 10 · Log Values You Must Memorise
Memorise three numbers (log 2, log 3, log 7) and you can compute almost every log NEET / JEE will ask.
| Number | log₁₀ value | Derivation |
|---|---|---|
| 1 | 0 | 10⁰ = 1 |
| 2 | 0.3010 | memorise |
| 3 | 0.4771 | memorise |
| 4 | 0.6020 | = 2 × log 2 |
| 5 | 0.6990 | = 1 − log 2 (since 5 = 10/2) |
| 6 | 0.7781 | = log 2 + log 3 |
| 7 | 0.8451 | memorise |
| 8 | 0.9030 | = 3 × log 2 |
| 9 | 0.9542 | = 2 × log 3 |
| 10 | 1 | 10¹ = 10 |
10.1 Natural log values
| Constant | Value |
|---|---|
ln 2 | 0.693 |
ln 3 | 1.099 |
ln 5 | 1.609 |
ln 10 | 2.303 |
ln e | 1 |
e | 2.718 |
10.2 Antilog mental estimates
| If log x ≈ | then x ≈ |
|---|---|
| 0 | 1 |
| 0.30 | 2 |
| 0.48 | 3 |
| 0.60 | 4 |
| 0.70 | 5 |
| 0.78 | 6 |
| 0.90 | 8 |
| 0.95 | 9 |
| 1 | 10 |
| 2 | 100 |
| 3 | 1000 |
log 250 = 2.398: the 2 (characteristic) comes from "digits before decimal − 1" — 250 has 3 digits → 2. The 0.398 (mantissa) is log 2.5.🧪 11 · Chemistry Applications of Logarithms
Every NEET Chemistry chapter that involves "very large" or "very small" numbers uses logs.
11.1 Ionic Equilibrium
pH = − log[H⁺] pOH = − log[OH⁻] pKa = − log Ka pKb = − log KbpH + pOH = 14 (at 25 °C) pKa + pKb = 14Henderson (acidic buffer): pH = pKa + log ([salt]/[acid])Weak acid: pH = ½ (pKa − log C)11.2 Chemical Kinetics
First-order: k = (2.303/t) · log([A]₀/[A])Half-life (first-order): t½ = 0.693/k = ln 2 / kArrhenius: log(k₂/k₁) = (Ea/2.303 R) · (1/T₁ − 1/T₂) | ln(k₂/k₁) = (Ea/R) · (1/T₁ − 1/T₂)11.3 Electrochemistry — Nernst
E = E° − (0.0591/n) · log Q (at 298 K)E° = (0.0591/n) · log K (at equilibrium)For H₂ electrode: E = − 0.0591 · pH11.4 Thermodynamics
ΔG° = − RT ln K = − 2.303 RT log KAt 298 K: ΔG° (kJ/mol) ≈ − 5.7 · log K11.5 Beer-Lambert Spectroscopy
A = log(I₀/I) = ε · b · cAbsorbance is base-10 log, not natural log. Transmittance T = I/I₀ ⇒ A = − log T.
⚛️ 12 · Physics Applications of Logarithms
12.1 Modern Physics — Radioactive decay
N(t) = N₀ · e−λt ⇒ ln(N/N₀) = − λtt = (2.303/λ) · log(N₀/N) t½ = ln 2 / λ = 0.693/λ12.2 Sound — Intensity Level
β (dB) = 10 · log(I/I₀)The decibel scale is logarithmic because the ear handles intensities over a billion-fold range. +10 dB = 10× intensity; +20 dB = 100× intensity.
12.3 Optics & Spectroscopy
Absorbance A = log(I₀/I)Magnitude scale (astronomy): m₁ − m₂ = − 2.5 log(F₁/F₂)12.4 Misc physics derivations using logs
- Capacitor RC charging: Q = Q₀(1 − e−t/τ) ⇒ t = − τ · ln(1 − Q/Q₀)
- Boltzmann distribution: ln(N₂/N₁) = − (E₂ − E₁)/(kT)
- Entropy (statistical): S = k · ln W
- Maxwell-Boltzmann ratio: ln(f(v₂)/f(v₁)) = − m(v₂² − v₁²)/2kT
📝 13 · Worked NEET / JEE Examples
If [H⁺] = 3.16 × 10⁻⁵, then pH = − log(3.16 × 10⁻⁵) = 5 − log 3.16 ≈ 5 − 0.5 = 4.5.
0.1 M acetic acid, Ka = 1.8 × 10⁻⁵. pKa = − log(1.8 × 10⁻⁵) = 5 − log 1.8 ≈ 5 − 0.255 = 4.745. pH = ½(pKa − log C) = ½(4.745 + 1) = 2.87.
k doubles from 300 K to 310 K. Find Ea.
log 2 = (Ea/2.303 R)(1/300 − 1/310). log 2 = 0.301. RHS factor = (10/300×310) ≈ 1.075×10⁻⁴. Ea = (0.301 × 2.303 × 8.314)/(1.075×10⁻⁴) ≈ 53.6 kJ/mol.
Cell with E° = 0.59 V and n = 1. log K = E°·n/0.0591 = 0.59/0.0591 = 10 → K = 10¹⁰.
k = 5 × 10⁻⁴ s⁻¹. t½ = 0.693/k = 0.693/(5 × 10⁻⁴) = 1386 s.
K = 10⁵ at 298 K. ΔG° = − 2.303 RT log K = − 2.303 × 8.314 × 298 × 5 = − 28.5 kJ/mol. Shortcut: ΔG° (kJ) ≈ − 5.7 × log K = − 5.7 × 5 = −28.5 kJ/mol.
Half-life 10 years. After 40 years, fraction remaining = (1/2)⁴ = 1/16. Equivalent log form: ln(N/N₀) = − λt = − 4 ln 2 → N/N₀ = e−4 ln 2 = 2−4 = 1/16. 1/16 of N₀.
Acetic acid + sodium acetate, both 0.1 M. pH = pKa + log(salt/acid) = pKa + log 1 = pKa = 4.74.
If transmittance T = 0.1, then A = − log 0.1 = 1. If T = 0.01, A = 2. Each unit of A = 10× drop in transmitted light.
Doubling sound intensity adds 10 log 2 ≈ 3 dB. Ten-fold increase adds 10 log 10 = 10 dB. Hundred-fold adds 20 dB.
🔑 14 · One-Page Cheat Sheet
The Three Rules NEET Tests in 90% of Questions
| Rank | Rule | Most common use |
|---|---|---|
| 1 | Product / Power log(xy) = log x + log y, log(xn) = n log x | pH, K calculations, kinetics |
| 2 | ln ↔ log ln x = 2.303 log x | Arrhenius, Nernst, radioactive decay |
| 3 | Inverse identity 10log x = x, eln x = x | antilog, finding [H⁺] from pH, finding N from ln(N/N₀) |
Anchor values
| Constant | Value |
|---|---|
| log 2 / log 3 / log 7 | 0.30 / 0.48 / 0.85 |
| ln 2 / ln 10 | 0.693 / 2.303 |
| 0.0591 V | = (2.303 RT/F) at 298 K — Nernst factor |
| 0.693/k | First-order half-life formula |
| 5.7 kJ/mol | = 2.303 RT at 298 K → ΔG° (kJ) ≈ −5.7 log K |
Sign quick check
- x > 1 → log x > 0
- x = 1 → log x = 0
- 0 < x < 1 → log x < 0
- x ≤ 0 → undefined