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NEET / JEE · Complete Reference

All Differentiation & Integration Rules for NEET

Every rule of calculus a NEET / JEE aspirant needs in one page — the five differentiation rules (constant, sum, product, quotient, chain), standard derivatives of every function class, implicit and logarithmic differentiation, then the full integration toolkit (basic table, substitution, by-parts, partial fractions, definite-integral properties) and the standard integral list. Every formula is paired with where it appears in Physics kinematics, electromagnetism, kinetics, and thermodynamics.

🧒 0 · Explained for a 10-year-old (with animation)

Before any formulas, here's what differentiation and integration really are — using two simple animated pictures.

0.1 Differentiation = "How fast is it changing right now?"

time → height slope > 0 (going up) slope = 0 (top of hill) slope < 0 (coming down) 🛼 The orange ball rolls along a hilly track Wherever the ball is, the steepness right under it = the derivative at that instant.

Think of riding a bike on a hilly road. Your speedometer doesn't show your total trip — it shows how fast you are going right at this moment. That's exactly what differentiation does.

You give it a curve (your height above the ground, your bank balance over time, the position of a ball), and at any point along that curve it tells you "how steeply is it changing right now?"

Going UP a hill

Slope is positive. The bigger the climb, the bigger the number. dy/dx > 0

At the TOP of a hill

Slope is zero — for a tiny moment you're flat. dy/dx = 0  (this is how we find peaks and valleys!)

Going DOWN a hill

Slope is negative. dy/dx < 0

Flat road

Slope is zero everywhere — nothing is changing. dy/dx = 0
🎈 In one sentence

Differentiation answers "how fast is something changing at this exact moment?"  In physics that becomes velocity (how fast position changes) and acceleration (how fast velocity changes).

0.2 Integration = "How much altogether?"

x → f(x) Total area = 🪣 Filling under the curve, one slice at a time Each thin orange slice has tiny width dx. Adding them all up = the integral.

Think of filling a swimming pool with a hose. The hose might run fast at first, slow down for a while, then speed up again. To know the total water in the pool after some time, you can't just look at the speed at one moment — you have to add up everything that has flowed.

Integration is the maths version of that adding-up. Take the curve (the flow rate, the height of a hill, anything), slice it into super-thin vertical strips, multiply each strip's height by its tiny width dx, and sum them all. The result is the total area under the curve — and it tells you how much water reached the pool, how far the car drove, or how much charge flowed through a wire.

Tall slices

Curve is high → each rectangle is tall → that section contributes a LOT to the total.

Short slices

Curve is low → small contribution. The "small bit" still counts!

Curve below zero

Slice points DOWN — counts as NEGATIVE area (water leaves the pool).

Thinner slices

The thinner you make them, the more accurate your total. In the limit (dx → 0) the answer is EXACT.
🎈 In one sentence

Integration answers "how much, in total, has happened?"  In physics that becomes distance (total of velocity over time), charge (total of current over time), or work (total of force over distance).

0.3 The two are opposites — the magic link

Position x(t) Velocity v(t) = dx/dt Acceleration a(t) = dv/dt differentiate ⟶ differentiate ⟶ ⟵ integrate ⟵ integrate ⇄ The two undo each other Differentiate to go forward · Integrate to go back · This is the Fundamental Theorem of Calculus.

If differentiation breaks something into "how fast" pieces, then integration glues them back together. Apply one and then the other, you get back what you started with — they are perfect opposites.

That is why every formula in this page comes in pairs. Every derivative on the left side has a matching integral on the right. Master the derivatives and the integrals become much easier — they are just derivatives read backwards.

1 · What is Differentiation?

Differentiation finds the instantaneous rate of change of a quantity — the slope of a curve at one point.

dy/dx = limΔx → 0 [y(x + Δx) − y(x)] / Δx
🎈 Plain English

Take two points on the curve very close together. Compute rise/run. Shrink the gap to zero. That number is the slope at the chosen point — its derivative.

1.1 Notation — three ways to write the same thing

NotationRead asUsed by
dy/dx"derivative of y with respect to x"Leibniz (standard NEET)
f′(x)"f-prime of x"Lagrange (most textbooks)
ẏ or ẋ"derivative w.r.t. time"Newton (physics)

1.2 The slope question for common curves

CurveSlope at any xSlope at x = 1
y = x11
y = x²2x2
y = x³3x²3
y = sin xcos xcos 1 ≈ 0.54
y = eˣe ≈ 2.72

2 · The Five Rules of Differentiation

RuleFormulaPlain meaning
Constantd/dx (c) = 0Constants don't change → slope is 0.
Constant multipled/dx (c · f) = c · f′Constants slide outside the derivative.
Sum / Differenced/dx (u ± v) = u′ ± v′Differentiate each piece, add/subtract.
Powerd/dx (xⁿ) = n · xⁿ⁻¹Drop the power down, subtract 1.
Productd/dx (u·v) = u′·v + u·v′"First × derivative of second + second × derivative of first."
Quotientd/dx (u/v) = (u′·v − u·v′) / v²Mind the minus sign and the v² in the denominator.
Chaind/dx (f(g(x))) = f′(g(x)) · g′(x)Differentiate outer, then multiply by derivative of inner.
🎈 Power rule memory trick

For xⁿ: "drop the power to the front, then drop the power by one." So x³ → 3x² · x → 1 · x⁵ → 5x⁴.

2.1 Tiny worked steps

📌 d/dx of 5x³ + 2x − 7

5·3·x² + 2 − 0 = 15x² + 2

📌 d/dx of (x² + 1)(x − 3) — product rule

u = x²+1, u′ = 2x. v = x−3, v′ = 1.
Result = 2x(x−3) + (x²+1)(1) = 2x²−6x + x²+1 = 3x² − 6x + 1

📌 d/dx of sin(3x²) — chain rule

Outer = sin(·), derivative = cos(·). Inner = 3x², derivative = 6x.
Result = cos(3x²) · 6x = 6x cos(3x²)

3 · Standard Derivatives — the must-know table

f(x)f′(x)f(x)f′(x)
c (constant)0xⁿn·xⁿ⁻¹
x11/x−1/x²
√x1/(2√x)∛x1/(3 x²⁄³)
aˣ · ln a
ln x1/xloga x1/(x · ln a)
|x|x/|x| (sign)eᵏˣk · eᵏˣ

4 · Trigonometric & Inverse Trig Derivatives

4.1 Trigonometric functions

f(x)f′(x)f(x)f′(x)
sin xcos xcos x−sin x
tan xsec²xcot x−cosec²x
sec xsec x · tan xcosec x−cosec x · cot x

4.2 Inverse trig functions

f(x)f′(x)Domain
sin⁻¹ x1/√(1 − x²)−1 < x < 1
cos⁻¹ x−1/√(1 − x²)−1 < x < 1
tan⁻¹ x1/(1 + x²)all x
cot⁻¹ x−1/(1 + x²)all x
sec⁻¹ x1/(|x|·√(x² − 1))|x| > 1
cosec⁻¹ x−1/(|x|·√(x² − 1))|x| > 1
🎈 Memory pattern

Every inverse-trig pair (sin⁻¹ / cos⁻¹, tan⁻¹ / cot⁻¹, sec⁻¹ / cosec⁻¹) has the same derivative magnitude with opposite signs.

5 · Exponential, Logarithmic & Hyperbolic

f(x)f′(x)
(its own derivative)
ekxk · ekx
ef(x)ef(x) · f′(x)
aˣ · ln a
ln x1/x
ln(f(x))f′(x)/f(x)
loga x1/(x · ln a)
sinh xcosh x
cosh xsinh x
tanh xsech²x

6 · Implicit & Logarithmic Differentiation

6.1 Implicit differentiation

Used when y is defined implicitly by an equation in x and y, not as y = f(x). Differentiate every term w.r.t. x, treating y as a function of x; collect dy/dx.

📌 Example

x² + y² = 25. Differentiate: 2x + 2y·(dy/dx) = 0 → dy/dx = −x/y.

6.2 Logarithmic differentiation — for y = (something)something

When the function has the variable in BOTH base and exponent (e.g. x^x, (sin x)cos x), use:

  1. Take ln of both sides.
  2. Use log laws to split into a sum.
  3. Differentiate both sides w.r.t. x.
  4. Multiply through by y.
📌 Example — y = xˣ

ln y = x · ln x.
(1/y) dy/dx = ln x + x · (1/x) = ln x + 1.
So dy/dx = xˣ (ln x + 1).

6.3 Parametric differentiation

If x = x(t) and y = y(t):

dy/dx = (dy/dt) / (dx/dt)
📌 Example — x = a cos θ, y = a sin θ

dx/dθ = −a sin θ. dy/dθ = a cos θ.
dy/dx = (a cos θ)/(−a sin θ) = −cot θ

7 · Higher-Order Derivatives

OrderSymbolPhysics meaning
1stdy/dx, f′(x)Velocity (when y is position, x is t)
2ndd²y/dx², f″(x)Acceleration
3rdd³y/dx³, f‴(x)Jerk (rarely tested)
nthdⁿy/dxⁿ, f(n)(x)General
📌 Example — SHM

If x(t) = A sin(ωt), then v = dx/dt = Aω cos(ωt), a = d²x/dt² = −Aω² sin(ωt) = −ω²x.
The minus sign in a = −ω²x is the signature of SHM.

8 · Where Differentiation Appears in NEET

8.1 Physics — Kinematics

v = dx/dt    a = dv/dt = d²x/dt²

8.2 Physics — Electromagnetism

EMF: ε = − dΦ/dt    (Faraday's law)
I = dQ/dt    VL = L · dI/dt

8.3 Physics — Maxima & Minima

To find a maximum or minimum of f(x):

  1. Solve f′(x) = 0 for stationary points.
  2. If f″(x) < 0 at that point → maximum (curve bends down).
  3. If f″(x) > 0 at that point → minimum (curve bends up).
⚛️ NEET classic

Projectile range R = (u²/g)·sin(2θ). Set dR/dθ = 0: cos(2θ) = 0 → θ = 45°. That's why 45° gives the maximum range.

8.4 Chemistry — Kinetics

Rate = − d[reactant]/dt = + d[product]/dt

8.5 Chemistry — Thermodynamics partials

(∂G/∂T)p = − S    (∂G/∂p)T = V
— End of Differentiation · Start of Integration —

9 · What is Integration?

Integration is the reverse of differentiation — it finds the function whose derivative is the given one. Geometrically, the definite integral of f(x) from a to b equals the area under the curve y = f(x) between x = a and x = b.

If F′(x) = f(x), then ∫ f(x) dx = F(x) + C
🎈 Plain English

If differentiation says "find the slope," integration says "given the slope at every point, find back the curve." The +C is the constant of integration — different curves can have the same slope (parallel curves shifted up or down).

9.1 Two basic properties

PropertyFormula
Constant multiple∫ c·f(x) dx = c · ∫ f(x) dx
Sum / Difference∫ [f(x) ± g(x)] dx = ∫ f(x) dx ± ∫ g(x) dx

10 · Standard Integral Table

10.1 Power, exponential, log

f(x)∫ f(x) dx
xⁿ (n ≠ −1)xⁿ⁺¹ / (n + 1) + C
1/xln|x| + C
eˣ + C
ekxekx/k + C
aˣ / ln a + C
1/(x + a)ln|x + a| + C

10.2 Trigonometric integrals

f(x)∫ f(x) dx
sin x−cos x + C
cos xsin x + C
tan x− ln|cos x| + C  or  ln|sec x| + C
cot xln|sin x| + C
sec xln|sec x + tan x| + C
cosec xln|cosec x − cot x| + C
sec²xtan x + C
cosec²x−cot x + C
sec x · tan xsec x + C
cosec x · cot x−cosec x + C

10.3 Inverse trig integrals

f(x)∫ f(x) dx
1/√(1 − x²)sin⁻¹ x + C
−1/√(1 − x²)cos⁻¹ x + C
1/(1 + x²)tan⁻¹ x + C
1/(|x|·√(x² − 1))sec⁻¹ x + C
⚡ Integration table = derivatives table read backwards. If you know derivatives cold, you know two-thirds of integrals automatically.

11 · Integration by Substitution

If the integrand contains a function and its derivative (or a near-multiple), substitute u = inner function.

∫ f(g(x)) · g′(x) dx = ∫ f(u) du   (where u = g(x))

11.1 Common patterns

IntegrandSubstituteResult
∫ (f(x))ⁿ · f′(x) dxu = f(x)(f(x))ⁿ⁺¹ / (n+1) + C
∫ f′(x)/f(x) dxu = f(x)ln|f(x)| + C
∫ f′(x) · ef(x) dxu = f(x)ef(x) + C
∫ sin(ax + b) dxu = ax + b−cos(ax+b)/a + C
∫ (ax + b)ⁿ dxu = ax + b(ax+b)ⁿ⁺¹ / [a(n+1)] + C
📌 Example

∫ 2x / (x² + 1) dx. Let u = x² + 1, du = 2x dx. Integral = ∫ du/u = ln|u| + C = ln(x²+1) + C.

12 · Integration by Parts

Used when the integrand is a product of two functions that don't share a clean substitution.

∫ u dv = u·v − ∫ v du

12.1 The "ILATE / LIATE" rule for picking u

Pick u from the function class that comes first in this priority list:

📌 Example — ∫ x · eˣ dx

u = x (algebraic), dv = eˣ dx. du = dx, v = eˣ.
∫ x eˣ dx = x · eˣ − ∫ eˣ dx = x eˣ − eˣ + C = eˣ (x − 1) + C

📌 Example — ∫ ln x dx

u = ln x, dv = dx. du = dx/x, v = x.
∫ ln x dx = x ln x − ∫ x · (1/x) dx = x ln x − x + C

12.2 Standard "by parts" result

∫ eˣ [f(x) + f′(x)] dx = eˣ · f(x) + C

13 · Special / Standard Integrals

These should be memorised cold — they appear repeatedly in NEET physics problems.

13.1 Quadratic-denominator integrals

IntegrandAnswer
1/(a² + x²)(1/a) · tan⁻¹(x/a) + C
1/(a² − x²)(1/2a) · ln|(a + x)/(a − x)| + C
1/(x² − a²)(1/2a) · ln|(x − a)/(x + a)| + C
1/√(a² − x²)sin⁻¹(x/a) + C
1/√(a² + x²)ln|x + √(a² + x²)| + C
1/√(x² − a²)ln|x + √(x² − a²)| + C

13.2 Square-root integrals

IntegrandAnswer
√(a² − x²)(x/2)√(a²−x²) + (a²/2) sin⁻¹(x/a) + C
√(a² + x²)(x/2)√(a²+x²) + (a²/2) ln|x + √(a²+x²)| + C
√(x² − a²)(x/2)√(x²−a²) − (a²/2) ln|x + √(x²−a²)| + C

13.3 Reduction-style

IntegrandAnswer
eᵃˣ · sin(bx)eax(a sin bx − b cos bx)/(a² + b²) + C
eᵃˣ · cos(bx)eax(a cos bx + b sin bx)/(a² + b²) + C

14 · Integration by Partial Fractions

For rational functions P(x)/Q(x) where deg(P) < deg(Q), split Q into simpler factors and write the rational as a sum.

Form of Q(x)Partial fraction
(x − a)(x − b)A/(x−a) + B/(x−b)
(x − a)²A/(x−a) + B/(x−a)²
(x − a)(x² + bx + c)A/(x−a) + (Bx + C)/(x² + bx + c)
(x² + bx + c)²(A x + B)/(x² + bx + c) + (Cx + D)/(x² + bx + c)²
📌 Example

∫ dx/(x² − 1) = ∫ dx / [(x−1)(x+1)] = ½ ∫ [1/(x−1) − 1/(x+1)] dx = ½ ln|(x−1)/(x+1)| + C

15 · Definite Integrals & Their Properties

ab f(x) dx = F(b) − F(a)   (where F′ = f)

This is the Fundamental Theorem of Calculus — it links differentiation and integration.

15.1 Properties of definite integrals

PropertyFormula
Reverse limitsab f(x) dx = − ∫ba f(x) dx
Same limitsaa f(x) dx = 0
Split pointab f(x) dx = ∫ac f dx + ∫cb f dx
King propertyab f(x) dx = ∫ab f(a + b − x) dx
Even integrand on (−a, a)= 2 · ∫0a f(x) dx if f(−x) = f(x)
Odd integrand on (−a, a)= 0 if f(−x) = −f(x)
Periodic (period T)0nT f(x) dx = n · ∫0T f(x) dx

15.2 Area under a curve

Area under y = f(x) between x = a and x = b is ∫ab f(x) dx (if f ≥ 0)
Area between two curves: ∫ab [fupper(x) − flower(x)] dx

16 · Where Integration Appears in NEET

16.1 Physics — Kinematics

v(t) = v₀ + ∫₀t a(t) dt    x(t) = x₀ + ∫₀t v(t) dt
⚛️ Plain English

If you know acceleration as a function of time, you INTEGRATE to find velocity. Integrate velocity to find position. Differentiation goes the other way (position → velocity → acceleration).

16.2 Physics — Work, Energy & Power

W = ∫ F · dx   (work done by a variable force)
U(x) = −∫ F(x) dx + C   (potential energy)

16.3 Physics — Electromagnetism

Q = ∫ I dt   (charge flowing in time interval)
V = ∫ E · dl   (potential difference)
Φ = ∫ B · dA   (magnetic flux)

16.4 Chemistry — Integrated rate laws

OrderDifferential formIntegrated form
Zero−d[A]/dt = k[A] = [A]₀ − kt
First−d[A]/dt = k[A]ln[A] = ln[A]₀ − kt
Second−d[A]/dt = k[A]²1/[A] = 1/[A]₀ + kt

16.5 Chemistry — Thermodynamic work

Wreversible isothermal = − nRT · ln(V2/V1) = − ∫V₁V₂ p dV

🔑 17 · One-Page Cheat Sheet

Differentiation

f(x)f′(x)
c0
xⁿn xⁿ⁻¹
aˣ ln a
ln x1/x
sin x / cos xcos x / −sin x
tan x / cot xsec²x / −cosec²x
sec x / cosec xsec x tan x / −cosec x cot x
sin⁻¹ x / cos⁻¹ x±1/√(1−x²)
tan⁻¹ x1/(1+x²)
Productu′v + uv′
Quotient(u′v − uv′)/v²
Chainf′(g(x))·g′(x)
Max / minf′ = 0; check sign of f″

Integration

f(x)∫ f(x) dx
xⁿ (n ≠ −1)xⁿ⁺¹/(n+1) + C
1/xln|x| + C
eˣ + C
aˣ/ln a + C
sin x−cos x + C
cos xsin x + C
sec²xtan x + C
1/(1+x²)tan⁻¹ x + C
1/√(1−x²)sin⁻¹ x + C
1/(a²+x²)(1/a) tan⁻¹(x/a) + C
1/√(a²−x²)sin⁻¹(x/a) + C
By parts∫ u dv = uv − ∫ v du  (ILATE)
Substitutionu = inner function; replace dx
Definiteab f dx = F(b) − F(a)
Memory anchors
1) Power → drop, subtract. Inverse: Power → add, raise.
2) Three product/quotient/chain rules + ILATE solve 90 % of NEET integrals.
3) The constants +C, ln a, and 1/(n+1) are the three things students forget most — flag them.